A cylinder of cooking gas is assumed to contain 11.2 kg of butane. The thermo chemical equation for the combustion of butane is : `C_(4)H_(10)(g)+(13)/(2)O_(2)(g)rarr 4CO_(2)(g)+5H_(2)O(l) , Delta H = -2658 kJ` If a family needs 15000 kJ of energy per day for cooking, how would the cylinder last ?
A cylinder of cooking gas is assumed to contain 11.2 kg of butane. The thermo chemical
A cylinder of cooking gas is assumed to contain 11.2 kg of butane. The thermo chemical equation for the combustion of butane is : `C_(4)H_(10)(g)+(13)/(2)O_(2)(g)rarr 4CO_(2)(g)+5H_(2)O(l) , Delta H = -2658 kJ` If a family needs 15000 kJ of energy per day for cooking, how would the cylinder last ?
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